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x^2+4=(x+2)(x+2)
We move all terms to the left:
x^2+4-((x+2)(x+2))=0
We multiply parentheses ..
x^2-((+x^2+2x+2x+4))+4=0
We calculate terms in parentheses: -((+x^2+2x+2x+4)), so:We get rid of parentheses
(+x^2+2x+2x+4)
We get rid of parentheses
x^2+2x+2x+4
We add all the numbers together, and all the variables
x^2+4x+4
Back to the equation:
-(x^2+4x+4)
x^2-x^2-4x-4+4=0
We add all the numbers together, and all the variables
-4x=0
x=0/-4
x=0
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